Chuong Nguyen U84536721 Post Lab Report Experiment 6 surface out B ( cytosine points) 1. (15 points) Prepare a table tilt the caboodle of the starting materials used and the trade of the dried mathematical result you collected. mastermind the percent supply for each compound. soften 1| | Part 2| | Material| mensuration| Material| Amount| KMnO4| 3.7580 g| [NiCl2(PPh3)2]| 0.6026 g| C5H8O2| 16.6 g| NH4SCN| 0.8024 g| Product| | PPh3| 2.0016 g| Mn(acac)3| 6.119 g| Product| | | | [Ni(NCS)2(PPh3)2]| 1.56 g| % deed over= mass of increase/ mass of reactant x 100% Part I 4 KMnO4 + 12 C5H8O2 4 Mn(C5H8O2)3 + 2 K2O + 7 O2 Theoretical yield 0.027 bulwark KMnO4 x 352.26 g/mol Mn(C5H8O2)3 (1:1 ratio) = 9.51 g Mn(C5H8O2)3 0.166 mol C5H8O2 x 352.26 g/mol Mn(C5H8O2)3 (3:1 ratio) = 19.47 g Mn(C5H8O2)3 Limiting reactant KMnO4 Mn(acac)3 %yield = 6.110 g /9.51 g KMnO4 x 100% = 64.25% Part II [NiCl2(PPh3)2] + 2NH4SCN [Ni(NCS)2(PPh3)2] + 2 NH4Cl Theoretical yield .6026 g /259.54g/mol[NiCl2(PPh3)2] x 304.80 g/mol [Ni(NCS)2(PPh3)2] (1:1 ratio) = 0.7076 g [Ni(NCS)2(PPh3)2] 0.8024 g/ 76.122g/mol NH4SCN x 304.80 g/mol [Ni(NCS)2(PPh3)2] (2:1 ratio) = 1.606 g Limiting reactant [NiCl2(PPh3)2] [Ni(NCS)2(PPh3)2] % yield = 1.56g / 0.7076 g x 100% = 220.
46 % (Excess triphenylphosphine need to account in chemical reply and product yield) 2. (15 points): Prepare a table listing both the experimental magnetic data you obtained for the three compounds you measured. From the data you accumulated, account the gee force ?g of your samples. Convert your gram susceptibility to hoagy suscepti bility, ?M. Compound| L| W| Ro| R| Mn(a! cac)3| 3.0 cm| 0.1744 g| -32| 1714| [NiCl2(PPh3)2]| 3.2 cm| 0.1333g| -32| 220| [Ni(NCS)2(PPh3)2]| 4.0 cm| 0.1414 g| -32| -56| ?g = 1.007 (L)(R-R0)/(109)(m) Mn(acac)3= 1.007(3)(1714- (-32)/ (0.1744 x 109) = 3.024 x10-5 [NiCl2(PPh3)2] = 1.007(3.2)(220 (-32)/ (0.1333 x 109) = 6.091 x 10-6 [Ni(NCS)2(PPh3)2] = 1.007(4)(-56 (-32)/ (0.1414 x...If you want to get a in effect(p) essay, put in it on our website: OrderCustomPaper.com
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